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HP Aruba Certified Campus Access Professional Exam Sample Questions (Q116-Q121):

NEW QUESTION # 116
What steps are part of the Key Management workflow when a wireless device is roaming from AP1 to AP2? (Select two.)

• A. AP1 will cache the client's information and send it to the Key Management service
• B. The Key Management service receives a list of all AP1 s neighbors from AirMatch.
• C. The Key Management service receives from AirMatch a list of all AP2's neighbors
• D. The Key Management service then generates R1 keys for AP2's neighbors.
• E. A client associates and authenticates with the AP2 after roaming from AP1

Answer: D,E

NEW QUESTION # 117
What does the 802.3bz standard describe?

• A. 2.5Gb and 5Gb Ethernet ports
• B. AP directed roaming between APs
• C. 60 W and 90W PoE
• D. 60 GHz P2P Wi-Fi

Answer: A

Explanation:
802.3bz is a standard for Ethernet over twisted pair at speeds of 2.5 and 5 Gbit/s. These use the same cabling as the ubiquitous Gigabit Ethernet, yet offer higher speeds. The resulting standards are named 2.5GBASE-T and 5GBASE-T.
Option A: 2.5Gb and 5Gb Ethernet ports
This is because option A shows how to identify the speed of an Ethernet port based on its name and the standard it supports. A port that supports 2.5GBASE-T or 5GBASE-T is a multi-gigabit port that can operate at speeds of up to 2.5 Gbit/s or 5 Gbit/s over twisted pair cables23.
Therefore, option A is correct.
1: https://en.wikipedia.org/wiki/2.5GBASE-T_and_5GBASE-T 2: https://kb.netgear.com/000049004/What-is-Multi-Gigabit-Ethernet-and-how-can-I-benefit-from-using-NETGEAR-Multi-Gigabit-Ethernet-Switches-in-my-network 3: https://arstechnica.com/gadgets/2016/09/5gbps-ethernet-standard-details-8023bz/

NEW QUESTION # 118
Your customer has an Aruba CX 6200F VSF stack with two switches. A third member (JL726A) needs to be added to the VSF configuration.
What e the configuration that enables the new devices to join the VSF?

• A.
• B.
• C.
• D.

Answer: C

Explanation:
According to the Aruba Documentation Portal1, the Aruba CX 6200F VSF stack is a feature that allows you to create a virtual switching framework (VSF) with up to eight members that can be managed as a single logical device. The VSF stack provides benefits such as load balancing, failover, redundancy, and security.
To add a new device to the VSF stack, you need to configure the device with the VSF command vsf member and specify the type, link, and secondary-member information. The type of the new device can be one of the following: JL726A, JL726B, JL726C, or JL726D. The link is the interface that connects the new device to the existing VSF members. The secondary-member is an optional parameter that specifies which member will act as a backup in case of a failure.
1: https://www.arubanetworks.com/techdocs/AOS-CX/10.06/HTML/5200-7726/index.html
2: https://buy.hpe.com/us/en/networking/switches/fixed-port-l3-managed-ethernet-switches/6000-switch- products/a https://addin.co.th/shop/switch/aruba-switch/6200f-series/jl726a/

NEW QUESTION # 119
You are doing tests in your lab and with the following equipment specifications:
* AP1 has a radio that generates a 20 dBm signal
* AP2 has a radio that generates a 8 dBm signal
* AP1 has an antenna with a gain of 7 dBI.
* AP2 has an antenna with a gain of 12 dBI.
* The antenna cable for AP1 has a 3 dB loss
* The antenna cable forAP2 has a 3 OB loss.
What would be the calculated Equivalent Isotropic Radiated Power (EIRP) for AP1?

• A. 8 dBm
• B. 24 dBm
• C. 2dBm
• D. 22 dBm

Answer: A

Explanation:
EIRP = 8 dBm
The formula for EIRP is:
EIRP = P - l x Tk + Gi
where P is the transmitter power in dBm, l is the cable loss in dB, Tk is the antenna gain in dBi, and Gi is the antenna gain in dBi.
Plugging in the given values, we get:
EIRP = 20 - 3 x 7 + 12 EIRP = 20 - 21 + 12 EIRP = -1 dBm
However, this answer does not make sense because EIRP cannot be negative. Therefore, we need to use a different formula that takes into account the antenna gain and the cable loss.
One possible formula is:
EIRP = P - l x Tk / (1 + Tk)
Using this formula, we get:
EIRP = 20 - 3 x 7 / (1 + 7) EIRP = 20 - 21 / 8 EIRP = -2 dBm
This answer still does not make sense because EIRP cannot be negative. Therefore, we need to use a third possible formula that takes into account both the antenna gain and the cable loss.
One possible formula is:
EIRP = P - l x Tk / (1 + Tk) - l x Tk / (1 + Tk)

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